Year :
2015
Title :
Mathematics (Core)
Exam :
WASSCE/WAEC MAY/JUNE
Paper 1 | Objectives
41 - 45 of 45 Questions
| # | Question | Ans |
|---|---|---|
| 41. |
 In the diagram, the shaded part is carpet laid in a room with dimensions 3.5m by 2.2m leaving a margin of 0.5m round it. Find area of the margin A. 4.7m2 B. 4.9m2 C. 5.7m2 D. 5.9m2 Detailed Solution
 Area of carpet = (3.5 - 0.5 - 0.5)m x (2.2 - 0.5 - 0.5)m 2.5m x 1.2m = 3m2 hence, area of margine = area of floor - area of carpet = (7.7 - 3)m2 = 4.7m2 |
|
| 42. |
Two angles of a pentagon are in the ratio 2:3. The others are 60o each. Calculate the smaller of the two angles A. 72o B. 100o C. 120o D. 144o Detailed Solution
 Two angles which are in the ratio 2:3 will have actual values 2xo, 3xo respectively. Thus 2xo + 3xo + 3 x 60 = 3x sum of angles of \(\Delta\)a i.e. 5xo + 180o = 3 x 180o 5xo + 180o = 540& |
|
| 43. |
A letter is selected from the letters of the English alphabet. What is the probability that the letter selected is from the word MATHEMATICS? A. \(\frac{9}{13}\) B. \(\frac{11}{26}\) C. \(\frac{4}{13}\) D. \(\frac{1}{26}\) Detailed SolutionTwo word mathematics is first rewritten as mathematics, since every letter of mathematics appears once in the english alphabet.Hence the probability that letter selected is from the word mathematics is prob. (matheics) = \(\frac{8}{26}\) = \(\frac{4}{13}\) |
|
| 44. |
In a circle radius rcm, a chord 16\(\sqrt{3}cm\) long is 10cmfrom the centre of the circle. Find, correct to the nearest cm, the value of r A. 22cm B. 17cm C. 16cm D. 15cm Detailed Solution
 |AM| = |MB| - \(\frac{|AB|}{2}\) = \(\frac{16\sqrt{3}}{2}\)cm = 8\(\sqrt{3}\)cm in \(\Delta\) AMO, r2 = |AM|Z + |MO|2 r2 = (8\(\sqrt{3}\))2 + 102 = 64 x 3 + 100 = 192 + 100 = 292 r = \(\sqrt{292}\) < |
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| 45. |
 In the diagram, \(\bar{OX}\) bisects < YXZ and \(\bar{OZ}\) bisects < YZX. If < XYZ = 68o, calculate the value of < XOZ A. 68o B. 72o C. 112o D. 124o Detailed Solution
 2(m + n) + 68o = 180o...(1) in \(\Delta\) XOZ, m + n + q = 180o ...(2) (m + n) = 180o - q...(3) substituting 180o - q for (m + n) in (1) gives 2(180o - q) + 68o = 180o |
| 41. |
In the diagram, the shaded part is carpet laid in a room with dimensions 3.5m by 2.2m leaving a margin of 0.5m round it. Find area of the margin A. 4.7m2 B. 4.9m2 C. 5.7m2 D. 5.9m2 Detailed Solution
Area of carpet = (3.5 - 0.5 - 0.5)m x (2.2 - 0.5 - 0.5)m 2.5m x 1.2m = 3m2 hence, area of margine = area of floor - area of carpet = (7.7 - 3)m2 = 4.7m2 |
|
| 42. |
Two angles of a pentagon are in the ratio 2:3. The others are 60o each. Calculate the smaller of the two angles A. 72o B. 100o C. 120o D. 144o Detailed Solution
Two angles which are in the ratio 2:3 will have actual values 2xo, 3xo respectively. Thus 2xo + 3xo + 3 x 60 = 3x sum of angles of \(\Delta\)a i.e. 5xo + 180o = 3 x 180o 5xo + 180o = 540& |
|
| 43. |
A letter is selected from the letters of the English alphabet. What is the probability that the letter selected is from the word MATHEMATICS? A. \(\frac{9}{13}\) B. \(\frac{11}{26}\) C. \(\frac{4}{13}\) D. \(\frac{1}{26}\) Detailed SolutionTwo word mathematics is first rewritten as mathematics, since every letter of mathematics appears once in the english alphabet.Hence the probability that letter selected is from the word mathematics is prob. (matheics) = \(\frac{8}{26}\) = \(\frac{4}{13}\) |
| 44. |
In a circle radius rcm, a chord 16\(\sqrt{3}cm\) long is 10cmfrom the centre of the circle. Find, correct to the nearest cm, the value of r A. 22cm B. 17cm C. 16cm D. 15cm Detailed Solution
|AM| = |MB| - \(\frac{|AB|}{2}\) = \(\frac{16\sqrt{3}}{2}\)cm = 8\(\sqrt{3}\)cm in \(\Delta\) AMO, r2 = |AM|Z + |MO|2 r2 = (8\(\sqrt{3}\))2 + 102 = 64 x 3 + 100 = 192 + 100 = 292 r = \(\sqrt{292}\) < |
|
| 45. |
In the diagram, \(\bar{OX}\) bisects < YXZ and \(\bar{OZ}\) bisects < YZX. If < XYZ = 68o, calculate the value of < XOZ A. 68o B. 72o C. 112o D. 124o Detailed Solution
2(m + n) + 68o = 180o...(1) in \(\Delta\) XOZ, m + n + q = 180o ...(2) (m + n) = 180o - q...(3) substituting 180o - q for (m + n) in (1) gives 2(180o - q) + 68o = 180o |