41 - 47 of 47 Questions
# | Question | Ans |
---|---|---|
41. |
The bearing of a point X from a point Y is 074°. What is the bearing of Y from X? A. 106o B. 146o C. 164o D. 254o E. 286o Detailed Solution< YXS = 74° (alternate angles, N\(_1\) S\(_1\) // N\(_2\) S\(_2\)) N\(_2\) E\(_2\) S\(_2\) = 180° \(\therefore\) Bearing of Y from X = 180° + 74° = 254° |
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42. |
The annual salary of Mr. Johnson Mohammed for 1989 was N12,000.00. He spent this on agriculture projects, education of his children, food items, saving , maintenance and miscellaneous items as shown in the pie chartHow much money did he invest in agriculture? A. N1,200.00 B. N1,440.00 C. N2,000.00 D. N2,910.00 E. N4,000.00 Detailed SolutionAgric project = \(\frac{120}{360} \times N12,000.00\)= \(N4,000.00\) |
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43. |
The table shows that the amount of money (in naira)collected through voluntary donations in a secondary school. What is the mode? A. N3 B. N6 C. N9 D. N12 E. N15 Detailed SolutionMode = 12 |
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44. |
The table shows that the amount of money (in naira)collected through voluntary donations in a secondary school. A. N3.00 B. N9.00 C. N12.00 D. N15.00 E. N18.00 |
C |
45. |
Table:Two groups of male students cast their votes on a particular proposal. The result are as follows:If a student in favor of the proposal is selected for a post, what is the probability that he is from group A? A. 8/19 B. 16/35 C. 10/19 D. 4/7 E. 4/5 Detailed SolutionProbability that a student in favor is group A= \(\frac{128}{128 + 32 + 96 + 48}\) = \(\frac{128}{304}\) = \(\frac{8}{19}\) |
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46. |
Table:Two groups of male students cast their vote on a particular proposal. The results are as follows:If a student is chosen at random, what is probability that he is against the proposal? A. 3/19 B. 4/19 C. 5/19 D. 9/19 E. 10/19 Detailed SolutionProbability that the student is against the proposal= \(\frac{32 + 48}{128 + 32 + 96 + 48}\) = \(\frac{80}{304}\) = \(\frac{5}{19}\) |
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47. |
The annual salary of Mr. Johnson Mohammed for 1989 was N12,000.00. He spent this on agriculture projects, education of his children, food items, saving , maintenance and miscellaneous items as shown in the pie chartHow much did he spend on food items? A. N9,700.00 B. N6,700.00 C. N2,000.00 D. N4,000.00 E. N2,300.00 Detailed SolutionDegree for food items = 360° - (120° + 80° + 43° + 30° + 18°)= 360° - 291° = 69° ∴∴ Amount spent on food items = \(\frac{69}{360}\)×12,000.00 = N2300.00 |
41. |
The bearing of a point X from a point Y is 074°. What is the bearing of Y from X? A. 106o B. 146o C. 164o D. 254o E. 286o Detailed Solution< YXS = 74° (alternate angles, N\(_1\) S\(_1\) // N\(_2\) S\(_2\)) N\(_2\) E\(_2\) S\(_2\) = 180° \(\therefore\) Bearing of Y from X = 180° + 74° = 254° |
|
42. |
The annual salary of Mr. Johnson Mohammed for 1989 was N12,000.00. He spent this on agriculture projects, education of his children, food items, saving , maintenance and miscellaneous items as shown in the pie chartHow much money did he invest in agriculture? A. N1,200.00 B. N1,440.00 C. N2,000.00 D. N2,910.00 E. N4,000.00 Detailed SolutionAgric project = \(\frac{120}{360} \times N12,000.00\)= \(N4,000.00\) |
|
43. |
The table shows that the amount of money (in naira)collected through voluntary donations in a secondary school. What is the mode? A. N3 B. N6 C. N9 D. N12 E. N15 Detailed SolutionMode = 12 |
|
44. |
The table shows that the amount of money (in naira)collected through voluntary donations in a secondary school. A. N3.00 B. N9.00 C. N12.00 D. N15.00 E. N18.00 |
C |
45. |
Table:Two groups of male students cast their votes on a particular proposal. The result are as follows:If a student in favor of the proposal is selected for a post, what is the probability that he is from group A? A. 8/19 B. 16/35 C. 10/19 D. 4/7 E. 4/5 Detailed SolutionProbability that a student in favor is group A= \(\frac{128}{128 + 32 + 96 + 48}\) = \(\frac{128}{304}\) = \(\frac{8}{19}\) |
|
46. |
Table:Two groups of male students cast their vote on a particular proposal. The results are as follows:If a student is chosen at random, what is probability that he is against the proposal? A. 3/19 B. 4/19 C. 5/19 D. 9/19 E. 10/19 Detailed SolutionProbability that the student is against the proposal= \(\frac{32 + 48}{128 + 32 + 96 + 48}\) = \(\frac{80}{304}\) = \(\frac{5}{19}\) |
|
47. |
The annual salary of Mr. Johnson Mohammed for 1989 was N12,000.00. He spent this on agriculture projects, education of his children, food items, saving , maintenance and miscellaneous items as shown in the pie chartHow much did he spend on food items? A. N9,700.00 B. N6,700.00 C. N2,000.00 D. N4,000.00 E. N2,300.00 Detailed SolutionDegree for food items = 360° - (120° + 80° + 43° + 30° + 18°)= 360° - 291° = 69° ∴∴ Amount spent on food items = \(\frac{69}{360}\)×12,000.00 = N2300.00 |