31 - 40 of 47 Questions
# | Question | Ans |
---|---|---|
31. |
In the diagram above PS||RQ, |RQ| = 6.4cm and perpendicular PH = 3.2cm. Find the area of SQR A. 5.12cm2 B. 9.60cm2 C. 10.24cm2 D. 20.48cm2 E. 40.96cm2 Detailed SolutionArea of a triangle = \(\frac{1}{2} \times b \times h\)Area of \(\Delta\) SQR = \(\frac{1}{2} \times 6.4 \times 3.2\) = 10.24 cm\(^2\) |
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32. |
Which angle is equal to ∠VWZ? A. ∠VXZ B. ∠VYX C. ∠XZW D. ∠YXZ E. ∠VYW Detailed Solution< VWZ = < VXZ (angles in the same segment) |
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33. |
Which triangle is equal in area to ΔVWZ A. ΔVXZ B. ΔVYZ C. ΔXYV D. ΔWYV E. ΔWYZ Detailed SolutionArea of \(\Delta\) VYZ = Area of \(\Delta\) VWZ (same base and within same parallel) |
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34. |
In the diagram above, PQRS s a cyclic quadrilateral, ∠PSR = 86o and ∠QPR = 38o. Calculate PRQ A. 58o B. 53o C. 48o D. 43o E. 38o Detailed SolutionPQR = 180o - 86o = 94o∴PRQ = 180o - 94o - 36o = 48o |
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35. |
In the diagram below, O is the center of the circle if ∠QOR = 290o, find the size ∠QPR A. 110o B. 70o C. 55o D. 35o E. 20o Detailed Solution360o - 290o = 70o70/2 = 35o |
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36. |
In the diagram above, PQ is a tangent at T to the circle ABT. ABC is a straight line and TC bisects ∠BTO. Find x. A. 20o B. 30o C. 35o D. 40o E. 50o Detailed SolutionFrom the figure < TAB = < BTQ = 40° (alternate segment)\(\therefore\)< ATB = 180° - (70° + 40°) = 70° (angle on a straight line) < BTC = \(\frac{40°}{2} = \frac{< BTQ}{2}\) \(\therefore < BTQ = 40°\) x° = 180° - (40° + 70° + 20°) = 50° |
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37. |
Which of the sketches above gives a correct method for constructed an angle of 120o at the point P? A. I only B. II only C. III only D. I and II only E. I, II and III |
D |
38. |
Use mathematical table to evaluate (cos40° - sin30°) A. -0.2660 B. -0.0266 C. 0.0266 D. 0.2660 E. 1.5320 Detailed Solution(cos 40° - sin 30°)= 0.7660 - 0.5 = 0.2660 |
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39. |
If the shadow of a pole 7m high is 1/2 its length what is the angle of elevation of the sun, correct to the nearest degree? A. 90o B. 63o C. 60o D. 26o E. 0o Detailed Solutiontan θ= 2.0000 θ = 63o |
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40. |
From the top of a building 10m high, the angle of depression of a stone lying on the horizontal ground is 69o. Calculate ,correct to one decimal place, the distance of the stone from the foot of the building A. 3.6m B. 3.8m C. 6.0m D. 9.3m E. 26.1m Detailed Solutionx = 10 tan 21o = 3.3839 = 3.8m |
31. |
In the diagram above PS||RQ, |RQ| = 6.4cm and perpendicular PH = 3.2cm. Find the area of SQR A. 5.12cm2 B. 9.60cm2 C. 10.24cm2 D. 20.48cm2 E. 40.96cm2 Detailed SolutionArea of a triangle = \(\frac{1}{2} \times b \times h\)Area of \(\Delta\) SQR = \(\frac{1}{2} \times 6.4 \times 3.2\) = 10.24 cm\(^2\) |
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32. |
Which angle is equal to ∠VWZ? A. ∠VXZ B. ∠VYX C. ∠XZW D. ∠YXZ E. ∠VYW Detailed Solution< VWZ = < VXZ (angles in the same segment) |
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33. |
Which triangle is equal in area to ΔVWZ A. ΔVXZ B. ΔVYZ C. ΔXYV D. ΔWYV E. ΔWYZ Detailed SolutionArea of \(\Delta\) VYZ = Area of \(\Delta\) VWZ (same base and within same parallel) |
|
34. |
In the diagram above, PQRS s a cyclic quadrilateral, ∠PSR = 86o and ∠QPR = 38o. Calculate PRQ A. 58o B. 53o C. 48o D. 43o E. 38o Detailed SolutionPQR = 180o - 86o = 94o∴PRQ = 180o - 94o - 36o = 48o |
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35. |
In the diagram below, O is the center of the circle if ∠QOR = 290o, find the size ∠QPR A. 110o B. 70o C. 55o D. 35o E. 20o Detailed Solution360o - 290o = 70o70/2 = 35o |
36. |
In the diagram above, PQ is a tangent at T to the circle ABT. ABC is a straight line and TC bisects ∠BTO. Find x. A. 20o B. 30o C. 35o D. 40o E. 50o Detailed SolutionFrom the figure < TAB = < BTQ = 40° (alternate segment)\(\therefore\)< ATB = 180° - (70° + 40°) = 70° (angle on a straight line) < BTC = \(\frac{40°}{2} = \frac{< BTQ}{2}\) \(\therefore < BTQ = 40°\) x° = 180° - (40° + 70° + 20°) = 50° |
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37. |
Which of the sketches above gives a correct method for constructed an angle of 120o at the point P? A. I only B. II only C. III only D. I and II only E. I, II and III |
D |
38. |
Use mathematical table to evaluate (cos40° - sin30°) A. -0.2660 B. -0.0266 C. 0.0266 D. 0.2660 E. 1.5320 Detailed Solution(cos 40° - sin 30°)= 0.7660 - 0.5 = 0.2660 |
|
39. |
If the shadow of a pole 7m high is 1/2 its length what is the angle of elevation of the sun, correct to the nearest degree? A. 90o B. 63o C. 60o D. 26o E. 0o Detailed Solutiontan θ= 2.0000 θ = 63o |
|
40. |
From the top of a building 10m high, the angle of depression of a stone lying on the horizontal ground is 69o. Calculate ,correct to one decimal place, the distance of the stone from the foot of the building A. 3.6m B. 3.8m C. 6.0m D. 9.3m E. 26.1m Detailed Solutionx = 10 tan 21o = 3.3839 = 3.8m |